The diver's speed when striking the water is 17.1 m/s.
To find the diver's speed when striking the water, we can use the equation:
vf = vi + at
We know that the initial speed (vi) is 2.50 m/s, the time (t) is 2.00 s, and the acceleration (a) is -9.8 m/s^2 (assuming downward as negative).
Plugging these values into the equation:
vf = 2.50 m/s + (-9.8 m/s^2) * 2.00 s
vf = 2.50 m/s - 19.6 m/s
vf = -17.1 m/s
Since speed cannot be negative, we take the magnitude of the result:
|vf| = |-17.1|
|vf| = 17.1 m/s
Therefore, the diver's speed when striking the water is 17.1 m/s.
The probable question may be:
If the diver leaves the board with an initial upward speed of 2.50 m/s, find the diver's speed when striking the water.