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Calculate the pH of the solution that results following addition of 11 mL of 1.0 MNaOH to 45 mL of 1.0 MNH₄Cl.

User Daniel Hao
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Final answer:

To calculate the pH of the solution resulting from the addition of 11 mL of 1.0 M NaOH to 45 mL of 1.0 M NH₄Cl, we can use the reaction between NH₄⁺ and OH⁻ to calculate the change in concentration of NH₄⁺ and NH₃ and determine the pH of the solution.

Step-by-step explanation:

To calculate the pH of the solution resulting from the addition of 11 mL of 1.0 M NaOH to 45 mL of 1.0 M NH₄Cl, we need to consider the reaction between NaOH and NH₄Cl. NaOH is a strong base, while NH₄Cl is a salt of a weak base (NH₄⁺) and a strong acid (Cl⁻). The reaction that occurs is:



NH₄⁺ + OH⁻ → NH₃ + H₂O



This reaction produces ammonia (NH₃) and water (H₂O). The NH₄⁺ ion reacts with the OH⁻ ion to form NH₃ and water. As a result, the concentration of NH₃ increases and the concentration of NH₄⁺ decreases.



Using the equation above, we can calculate the change in concentration of NH₄⁺ and NH₃ and use it to determine the pH of the solution.

User Akro
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