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If y varies directly with x and y=8 when x=2, find y when x=1.

User Bluee
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Final answer:

To find y when x=1 for a relationship where y varies directly with x and y=8 when x=2, we first determine the constant of proportionality, k, then apply it to find y = 4 when x = 1. Therefore, when x is 1, the value of y is 4.

Step-by-step explanation:

When y varies directly with x, it means that if x increases, y increases, and if x decreases, y decreases by the same factor. This can be represented by the equation y = kx, where k is the proportionality constant. Given that y = 8 when x = 2, we can first find the constant of proportionality by substituting these values into the equation: 8 = k(2), which simplifies to k = 4. This means the relationship between x and y can be written as y = 4x.

Now, to find y when x=1, we substitute 1 for x in the equation: y = 4(1), which gives us y = 4. Therefore, when x is 1, the value of y is 4.

User Keithgaputis
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