Final answer:
To determine the volume of a 1.85 M Li3PO4 solution containing 0.237 moles of Li3PO4, use the equation Volume (L) = Moles / Molarity. The volume is calculated to be 0.128 liters.
Step-by-step explanation:
To determine the volume of a solution, we can use the equation:
Volume (L) = Moles / Molarity
Given that the solution has a concentration of 1.85 M and contains 0.237 moles of Li3PO4, we can substitute these values into the equation:
Volume (L) = 0.237 moles / 1.85 M
Volume (L) = 0.128 L
Therefore, the volume of the 1.85 M Li3PO4 solution that contains 0.237 moles of Li3PO4 is 0.128 liters.