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Determine the volume of a 1.85 M Li3 PO 4 solution that contains 0.237 moles of Li3 PO 4

1 Answer

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Final answer:

To determine the volume of a 1.85 M Li3PO4 solution containing 0.237 moles of Li3PO4, use the equation Volume (L) = Moles / Molarity. The volume is calculated to be 0.128 liters.

Step-by-step explanation:

To determine the volume of a solution, we can use the equation:

Volume (L) = Moles / Molarity

Given that the solution has a concentration of 1.85 M and contains 0.237 moles of Li3PO4, we can substitute these values into the equation:

Volume (L) = 0.237 moles / 1.85 M
Volume (L) = 0.128 L

Therefore, the volume of the 1.85 M Li3PO4 solution that contains 0.237 moles of Li3PO4 is 0.128 liters.

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