Final answer:
To burn 9340 L of acetylene, 3.335 tanks of oxygen are required, which means 4 tanks when rounded up.
Step-by-step explanation:
The question is asking about the chemical reaction involved when using an oxyacetylene torch, specifically regarding the volume of oxygen needed to fully burn a given volume of acetylene gas. According to the balanced chemical equation provided:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
For every 2 volumes of acetylene, 5 volumes of oxygen are required for complete combustion. Given that one tank provides 9340 L of acetylene, you would need 2.5 times as much oxygen. Since each oxygen tank provides 7.00 × 10³ L, you divide the total volume of oxygen needed by this amount to find the number of tanks required.
Calculation: 9340 L C₂H₂ × (5 / 2) = 23350 L O₂ needed. Each tank provides 7000 L O₂, so 23350 L / 7000 L/tank = 3.335 tanks. Therefore, you will need 4 tanks of oxygen (rounding up, as you can't have a fraction of a tank).