Question

What will the following C++ 11 code display?

vector numbers { 3, 5 };

for (int val : numbers)
cout << val << endl;

A) 5
5
5

B) 3
3
3
3
3

C) 3
5

D) Nothing. This code has an error.

Answer 1

The code will output the numbers '3' and '5', each on a new line, as it iterates over a vector containing these two elements using a range-based for loop.

Step-by-step explanation:

The given C++11 code initializes a vector named numbers with two elements: 3 and 5. It then uses a range-based for loop to iterate over each element in the vector and outputs them to the console followed by a newline character. Since the vector contains two elements, the loop will run twice: first, printing '3' and then '5', both followed by a newline.

Therefore, the output of the code will be:

3
5

Each value from the vector is printed on a separate line because of the endl that inserts a newline character after each output.