Question

What is the output of the following program?

#include
using namespace std;

void showDub(int);

int main()
{
int x = 2;

showDub(x);
cout << x << endl;
return 0;
}

void showDub(int num)
{
cout << (num * 2) << endl;
}

A) 2
2

B) 4
2

C) 2
4

D) 4
4

Answer 1

The program prints '4' followed by '2' since the function showDub prints the doubled value without modifying the original variable. Thus, the output is '4 2'.

Step-by-step explanation:

The given C++ program defines a function showDub that takes an integer, doubles it, and prints it to the console. The function is called in the main function with x as an argument, where x is initially set to 2. The showDub function prints 2 * 2, which is 4. After that, the original value of x is printed in the main function, which remains 2 since the modification in showDub does not affect the original variable. Therefore, the output of the program is:

1. 4
2. 2

The correct answer is option B) 4 2.