Question

Nolan has five more quarters and dimes and seven fewer nickels and dimes. He has 25 coins. How many of each coin does he have? How much money in dollars and cents is it worth?

Answer 1

He has 2 nickels, 9 dimes, and 14 quarters, with a total value of $4.50

Explanation:

I am going to assume that the "and" in "five more quarters and dimes" and the "and" in "seven fewer nickels and dimes" is actually "than" because otherwise, there is no context in this question. If my answer is incorrect, please tell me how to correctly interpret this question.

In this scenario, the "and" in "five more quarters and dimes" and the "and" in "seven fewer nickels and dimes" is actually "than."

Amount of nickels - x

If there are seven fewer nickels than dimes, the amount of dimes is x + 7. There are five more quarters than dimes, so the amount of quarters is x + 7 + 5, which equals x + 12.

1. x + x + 7 + x + 12 = 25
2. 3x + 19 = 25
3. 3x = 6
4. x = 2

Therefore, there are 2 nickels. Now we must figure out the number of quarters and dimes.

x + 7 = 9

x + 12 = 14

There are 9 dimes and 14 quarters.

Nickels are each worth 5 cents. 2 times 5 is 10 cents.

Dimes are each worth 10 cents. 9 times 10 is 90 cents.

Quarters are each worth 25 cents. 14 times 25 is 350 cents.

Now, we add. 10 + 90 + 350 = 100 + 350 = 450.

REMEMBER, THIS IS IN CENTS. WE MUST STILL CONVERT IT INTO DOLLARS.

450 divided by 100 is $4.50

Answer 2

9 dimes, 4 nickels, 12 quarters

90 cents + 20 cents + 300 cents = 410 cents = $6.83

Explanation:

q=5+d

n=d-7

q+n+d=25

5 + d + d - 7 + d = 25

3d-2=25

3d=27

d=9

25 - 9 = 16 nickels and quarters

q + n = 16 ---> q=16-n

n=d-7 ---> d=n+7

q=5 + n + 7

q=n+12

n+12 = 16-n

2n=4

n=4

25-(9+4)= 12 quarters