The quadratic equation x² + 8x - 4 = 10 is solved by rearranging to x² + 8x - 14 = 0, applying the quadratic formula, yielding solutions -4 + √30 and -4 - √30.
To solve the quadratic equation x² + 8x - 4 = 10, we need to rearrange the equation to get 0 on one side:
x² + 8x - 14 = 0
Next, we can use the quadratic formula to find the solutions for x:
x = (-b ± √(b² - 4ac)) / (2a)
Plugging in the values from the equation, we get:
x = (-8 ± √(8² - 4 * 1 * -14)) / (2 * 1)
Simplifying further, we have:
x = (-8 ± √(64 + 56)) / 2
x = (-8 ± √120) / 2
x = (-8 ± 2√30) / 2
x = -4 ± √30
So, the solutions for x are approximately -4 + √30 and -4 - √30.
The question probable may be
What are the solutions to the quadratic equation x² + 8x - 4 = 10, and how are they obtained using the quadratic formula?