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x2 + 8x – 4 = 10

User Webdeb
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1 Answer

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The quadratic equation x² + 8x - 4 = 10 is solved by rearranging to x² + 8x - 14 = 0, applying the quadratic formula, yielding solutions -4 + √30 and -4 - √30.

To solve the quadratic equation x² + 8x - 4 = 10, we need to rearrange the equation to get 0 on one side:

x² + 8x - 14 = 0

Next, we can use the quadratic formula to find the solutions for x:

x = (-b ± √(b² - 4ac)) / (2a)

Plugging in the values from the equation, we get:

x = (-8 ± √(8² - 4 * 1 * -14)) / (2 * 1)

Simplifying further, we have:

x = (-8 ± √(64 + 56)) / 2

x = (-8 ± √120) / 2

x = (-8 ± 2√30) / 2

x = -4 ± √30

So, the solutions for x are approximately -4 + √30 and -4 - √30.

The question probable may be

What are the solutions to the quadratic equation x² + 8x - 4 = 10, and how are they obtained using the quadratic formula?

User Schlenk
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