Answer:
9^2 (9 to the power of 2)
Explanation:
Ok, this is how you find exponents:
Well, exponents are really just abbreviated multiplication, so to find the numerical value of 9^5 and 9^3, you need to multiply 9 by itself 5 times and 3 times, then divide.
9*9*9*9*9= 59049
9*9*9= 729
Then you divide: 59049/729= 81.
But the question asks to rewrite the answer using a single positive exponent, so now we simplify 81 into an exponent.
The square root of 81= 9
9*9=81
81 as an exponent= 9^2 (or 9 multiplied 2 times)
Another simple trick for solving exponents is to subtract the exponents:
9^5-9^3= 9^2 (5-3=2)
I hope this answer was helpful!