Answer:
Explanation:
You have segment RT of length 77 with point S on it dividing it into segments RS=6y+3 and ST=5y+8. You want to know the value of y and the lengths of segments RS and ST.
Segment sum theorem
The segment sum theorem tells you the whole is the sum of the parts:
RS +ST = RT
(6y +3) +(5y +8) = 77 . . . . . use given values
Solution
11y +11 = 77 . . . . . . . . . . . . collect terms
y +1 = 7 . . . . . . . . . . . . . . . divide by 11
y = 6 . . . . . . . . . . . . . . . . . subtract 1
The lengths of the parts are ...
RS = 6y +3 = 6(6) +3 = 39
ST = 5y +8 = 5(6) +8 = 38