Question

While watching a car move down the street, you close your eyes and count off

14
seconds. When you open your eyes again, the car is
158
feet further down the road from where you last saw it.

WHAT IF the car traveled at a constant speed while your eyes were closed? How fast would it have had to travel?

a. What constant speed would allow the car to travel exactly
158
feet in exactly
14
seconds?

Correct Correct

b. If a car traveled at this speed for
t
seconds, what formula would model its distance
d
(in feet) from the starting point in terms of the time elapsed,
t
(in seconds)? Recall that this does not necessarily represent the actual relationship between the distance traveled and time elapsed for the real car. This represents the relationship for an imaginary car traveling at a constant speed.

Incorrect

Answer 1

a) The constant speed at which the car would have to travel, using the distance, time, and speed formula is approximately 11.29 feet per second.

b. If a car travels at this speed for t seconds, the formula that would model its distance d (in feet) from the starting point in terms of the time elapsed, t (in seconds) is d = 11.2857t.

The distance, time, and speed formulas are:

1. Speed = distance ÷ time
2. Distance = speed × time
3. Time = distance ÷ speed

The time that elapsed when your eyes are closed = 14 seconds

The distance of the car further down the road = 158 feet

a) The constant speed at which the car would have to travel, using the formula:

Speed = distance/time

Speed = 158 feet / 14 seconds speed

≈ 11.29 feet per second

Thus, the car would have had to travel approximately 11.29 feet per second to cover the 158 feet in 14 seconds.

b. The distance, d (in feet) from the starting point in terms of the time elapsed, t (in seconds) is distance = speed × time.

d = 11.2857t