Final answer:
According to the ideal gas law at STP where the pressure is 1 atm and temperature is 273 K, the volume of 1 mole of an ideal gas is 22.4 L. Therefore, the value of the ratio between moles (assuming 1 mole), gas constant R, temperature, and pressure is 22.4, which corresponds to option D.
Step-by-step explanation:
The question refers to the ideal gas law at standard temperature and pressure (STP), which is 0°C (273 K) and 1 atm. The ideal gas law is represented by the formula PV = nRT, where P is pressure, V is volume, n is moles, R is the gas constant, and T is temperature. At STP, the volume of 1 mole of an ideal gas is 22.4 L, and the gas constant (R) is typically used as 0.0821 (L.atm)/(K.mol).
To find the ratio between moles (assuming 1 mole), the gas constant R, temperature and pressure at STP, you would rearrange the ideal gas law to solve for the volume (V = nRT/P). Plugging in the values at STP, we get V = (1 mol)(0.0821 L.atm/(K.mol))(273 K)/(1 atm), which calculates to approximately 22.4 L. Hence, the molar volume of a gas at STP is 22.4 L/mol and that gives us the answer to the question which is option D: 22.4.