Final answer:
The difference in volume before and after compressing a 1 mol sample of ammonia gas is 11.20 L.
Step-by-step explanation:
The volume of an ideal gas can be calculated using the ideal gas law, which states:
V = nRT / P
Where V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)), T is the temperature in Kelvin, and P is the pressure.
Using the given information:
Initial volume (V1) = V1 = nRT1 / P1 = (1 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm) = 22.41 L
Final volume (V2) = V2 = nRT2 / P2 = (1 mol)(0.0821 L·atm/(mol·K))(273 K) / (2 atm) = 11.21 L
Therefore, the difference in volume before and after compression is: 22.41 L - 11.21 L = 11.20 L