Question

What are the components of a 20 m/s velocity that is directed 10 degrees above the horizontal

Answer 1

To find the components of a 20 m/s velocity directed 10 degrees above the horizontal, use trigonometric functions: horizontal component (Vx) is approximately 19.7 m/s, and vertical component (Vy) is approximately 3.5 m/s.

Step-by-step explanation:

The components of a 20 m/s velocity that is directed 10 degrees above the horizontal can be found using trigonometric functions. The horizontal component (Vx) of the velocity is Vx = Vcos(θ), and the vertical component (Vy) of the velocity is Vy = Vsin(θ), where V is the magnitude of the velocity and θ is the angle above the horizontal.

For a velocity of 20 m/s directed 10 degrees above the horizontal:

• Horizontal Component (Vx) = 20 m/s * cos(10°) = 19.7 m/s (approximately)
• Vertical Component (Vy) = 20 m/s * sin(10°) = 3.5 m/s (approximately)

Answer 2

The components of a 20 m/s velocity directed 10 degrees above the horizontal are 19.83 m/s horizontally and 3.47 m/s vertically.

To find the components of velocity, we can use trigonometry. Given that the velocity magnitude is 20 m/s and it is directed 10 degrees above the horizontal, we can determine the horizontal and vertical components.

The horizontal component of the velocity is given by Vx = V * cos(angle), where V is the magnitude and angle is the angle of direction. Substituting the values, Vx = 20 m/s * cos(10 degrees) = 19.83 m/s.

The vertical component of the velocity is given by Vy = V * sin(angle), where V is the magnitude and angle is the angle of direction. Substituting the values, Vy = 20 m/s * sin(10 degrees) = 3.47 m/s.

Therefore, the components of a 20 m/s velocity directed 10 degrees above the horizontal are 19.83 m/s horizontally and 3.47 m/s vertically.