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An ambulance driver is rushing a patient to the hospital. While traveling at 72 km/h, she notices the traffic light at the upcoming intersections has turned amber. To reach the intersection before the light turns red, she must travel 50 m in 2.0 s. (a) What minimum acceleration must the ambulance have to reach the intersection before the light turns red? (b) What is the speed of the ambulance when it reaches the intersectio

User JoachimR
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2 Answers

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Final answer:

To avoid running a red light, the minimum acceleration required by the ambulance is 5 m/s², and its speed when reaching the intersection will be 30 m/s.

Step-by-step explanation:

Calculating Acceleration and Final Speed

To answer question 90 regarding the ambulance driver facing a traffic light situation:

(a) Required Acceleration

To find the minimum acceleration the ambulance must have to reach the intersection in 2.0 seconds, we use the formula:
s = ut + ½at²

Where:

s is the distance (50 m)

u is the initial velocity (72 km/h, which is 20 m/s)

t is the time (2.0 s)

a is the acceleration (which we want to find)

Rearranging for a, we have:

a = 2(s - ut) / t²

Plugging in the numbers:

a = 2(50 m - 20 m/s × 2.0 s) / (2.0 s)²

a = 2(50 m - 40 m) / 4.0 s²

a = 2(10 m) / 4.0 s²

a = 20 m / 4.0 s²

a = 5 m/s²

The minimum acceleration needed is 5 m/s².

(b) Final Velocity of the Ambulance

To find the velocity of the ambulance when it reaches the intersection, we use the formula:
v = u + at

Where:

v is the final velocity

u is the initial velocity (20 m/s)

a is the acceleration (5 m/s²)

t is the time (2.0 s)

Plugging in the numbers:

v = 20 m/s + 5 m/s² × 2.0 s

v = 20 m/s + 10 m/s

v = 30 m/s

The ambulance's speed when it reaches the intersection is 30 m/s.

User Mahdi Jokar
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5 votes

(a) The minimum acceleration required is 5 m/s².

(b) The speed of the ambulance when it reaches the intersection is 82 m/s.

To determine the minimum acceleration needed for the ambulance to reach the intersection before the traffic light turns red, we can use the kinematic equation d=ut+ 1/2 at^2, where d is the distance, u is the initial velocity, t is the time, and a is the acceleration. In this case, the ambulance needs to cover a distance of 50 m in 2.0 seconds with an initial speed of 72 km/h. Converting the speed to meters per second (20m/s), we can rearrange the formula to solve for acceleration (a), yielding a minimum acceleration of 5m/s^2.

Next, to find the speed of the ambulance when it reaches the intersection, we use the kinematic equation v=u+at, where v is the final velocity. With the determined acceleration of 5m/s^2 and the initial velocity of 20m/s, we find that the speed of the ambulance when it reaches the intersection is 82m/s. These calculations demonstrate the relationship between acceleration, initial speed, and distance traveled, providing crucial information for the ambulance driver to reach the intersection before the traffic light turns red.

User Junkystu
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