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The order of impulse conduction in the heart, from beginning to end, is __________.

A) SA node, bundle branch, AV node, bundle of his, and purkinje fibers
B) SA node, bundle of his, AV node, bundle branch and parkinje fibers
C) SA node, AV node, bundle of his, bundle branch, and purkinje fibers
D) SA node, bundle branches, bundle of His, AV node, and Purkinje fibers

User Slim Sim
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Final answer:

The order of impulse conduction in the heart is SA node, AV node, bundle of His, bundle branches, and Purkinje fibers, which coordinate heart contractions from atria to ventricles.

Step-by-step explanation:

The correct order of impulse conduction in the heart, from beginning to end, is option C) SA node, AV node, bundle of His, bundle branch, and purkinje fibers. The sequence starts with the generation of an electric charge by the SA node (sinoatrial node), which causes the atria to contract. This impulse then travels to the AV node (atrioventricular node), where there is a brief pause that allows the atria to finish contracting and pumping blood into the ventricles. After this pause, the impulse proceeds to the bundle of His, which is an atrioventricular bundle, and then divides into the right and left bundle branches.

These branches spread the impulse through the interventricular septum and the impulse finally reaches the Purkinje fibers. The Purkinje fibers sharply conduct the impulse through the ventricles, causing them to contract and pump blood to the body during systole.

User NHG
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