The work done during the isobaric expansion is 66 J. The heat absorbed from the surroundings is 5251.76 J. The changes in internal energy and enthalpy during the isobaric expansion are 5185.76 J.
To calculate the work done, we can use the formula: work = pressure * change in volume. Here, the pressure is constant at 1.1 atm (given as 101.3 J), and the change in volume is 100 L - 40 L = 60 L. Therefore, work = 1.1 atm * 60 L = 66 J.
The heat absorbed from the surroundings during an isobaric process can be calculated using the formula: heat = n * Cv * change in temperature. Here, n is the number of moles of the gas (16.26 moles), Cv is the specific heat at constant volume (12 g·mol⁻¹·K⁻¹), and the change in temperature is the final temperature minus the initial temperature (27°C - 0°C = 27 K). Therefore, heat = 16.26 moles * 12 g·mol⁻¹·K⁻¹ * 27 K = 5251.76 J.
The change in internal energy during an isobaric process is given by: change in internal energy = heat - work. Therefore, change in internal energy = 5251.76 J - 66 J = 5185.76 J.
The change in enthalpy during an isobaric process is equal to the change in internal energy. Therefore, change in enthalpy = change in internal energy = 5185.76 J.