Final answer:
The two numbers with an average of 12, where one number is 5 more than the other, are 9.5 and 14.5.
Step-by-step explanation:
The question involves finding two numbers given that their average is 12 and one number is 5 more than the other.
To solve this, let’s denote the smaller number as x.
Since one number is 5 more than the other, the larger number will be x + 5.
The average of these two numbers is (x + (x + 5))/2 = 12.
Multiplying both sides by 2 gives 2x + 5 = 24.
Subtracting 5 from both sides, we get 2x = 19, and then dividing both sides by 2 results in x = 9.5.
Therefore, the two numbers are 9.5 and 9.5 + 5, which gives us 9.5 and 14.5.