Question

A 6.0-mH inductor is in a series circuit with a resistor and an ideal battery. At the instant the current in the circuit is 5.0A the energy stored in the inductor is:

a) 0
b) 7.5ᴇ−2 J
c) 15ᴇ−2 J
d) 30ᴇ−2 J
e) unknown since the rate of change of the current is not given

Answer 1

The energy stored in the inductor is
`7.5 * 10^(-3) J.`

Step-by-step explanation:

To find the energy stored in the inductor, we can use the formula:

`E = (1/2) * L * I^2`

where E is the energy stored in the inductor, L is the inductance, and I is the current. We are given that the inductance is 6.0 mH and the current is 5.0 A. Substituting these values into the formula, we get:

`E = (1/2) * 6.0 * 10^(-3) * (5.0)^2 = 7.5 * 10^(-3) J`

Therefore, the energy stored in the inductor is
`7.5 * 10^(-3) J.`