Question

Immediately after switch S in the circuit shown is closed, the current through the battery is:

a.0
b.V/R1
c. V/R2
d.V/(R1 + R2)
e.V(R1 + R2)/(R1R2)

Answer 1

Immediately after the switch in the circuit is closed, the current through the battery would be the total voltage V divided by the combined resistance of R1 and R2 in series, corresponding to option (d) V/(R1 + R2).

Step-by-step explanation:

When the switch in the circuit is closed at t = 0 s, the current through the battery would be V/(R1 + R2), which corresponds to option (d). This result comes from applying Ohm's law, which states that current (I) equals voltage (V) divided by resistance (R). With the switch closed, both resistors R1 and R2 are in series and their resistances add up. The total resistance is R1 + R2, and so the total current from the battery immediately after closing the switch is the total voltage V divided by the total resistance R1 + R2.