Question

A 10-turn conducting loop with a radius of 3.0 cm spins at 60 revolutions per second in a magnetic field of 0.50T. The maximum emf generated is:

a) 0.014 V
b) 0.53 V
c) 5.3V
d) 18V
e) 180 V

Answer 1

The maximum emf generated by a spinning conducting loop can be calculated using the formula emf = NΦω, where N is the number of turns, Φ is the magnetic flux, and ω is the angular velocity. In this case, the maximum emf is approximately 0.53 V.

Step-by-step explanation:

The maximum emf generated by a spinning conducting loop can be calculated using the formula:

emf = NΦω

Where N is the number of turns in the loop, Φ is the magnetic flux through the loop, and ω is the angular velocity of the loop.

1. First, calculate the magnetic flux using the formula:
2. Φ = BA
3. Where B is the magnetic field and A is the area of the loop.
4. Then, find the angular velocity using the formula:
5. ω = 2πf
6. Where f is the frequency of rotation.
7. Finally, substitute the values into the formula for emf:
8. emf = NΦω

Following these steps, the maximum emf generated in the given scenario is approximately 0.53 V.