Question

Write the equation of a line in slope intercept form given;
(6,-3), (0, 5)

Answer 1

`y=(-4/3)x+5`

Explanation:

so you want to start by using y=mx+b

step one: find the slope (remember m is the slope in this)

m=
`(y2-y1)/(x2-x1)`

m=
`(5+3)/(0-6)`

m=
`(8)/(-6)`

m= -
`(4)/(3\\)`

step two: insert the value we found for m into the equation and take one of the given points and insert the x and y into the equation (im using (0,5)) and solve for b.

y=mx+b

5= -4/3(0)+b

5=b

step three: rewrite y=mx+b with the values we found for m and for b

`y=(-4/3)x+5`