Final answer:
The resultant magnetic force on the two equal sides of a right triangle loop of wire in a uniform magnetic field parallel to the hypotenuse is zero because the force depends on the sine of the angle between the wire and the field, which is zero when they are parallel.
Step-by-step explanation:
The student asked about the resultant magnetic force on two equal sides of a right triangle loop of wire carrying a current in a uniform magnetic field. Given that the field is parallel to the hypotenuse of the triangle, the force on each of the two equal sides will be perpendicular to the magnetic field and thus will not experience any force due to being aligned with the field. Hence, the forces on these equal sides will be zero because the force on a current-carrying wire in a magnetic field is given by F = I * l * B * sin(θ), where F is the force, I is the current, l is the length of the wire, B is the magnetic field strength, and θ is the angle between the field and the wire. If the wire is aligned with the field (θ = 0° or θ = 180°), sin(θ) is zero, so the force is zero. This follows a physical principle where there is no magnetic force on a segment of wire when it is parallel to the magnetic field lines.