141k views
3 votes
J.J. Thompson's experiment, involving the motion of an electronbeam in mutually perpendicular E and B fields, gave the value of:

A. Mass of electron
B. Earth's magnetic field
C. charge/mass ratio for electron
D. Avogadro's number

User Jagan K
by
7.9k points

1 Answer

5 votes

Final answer:

J.J. Thomson's experiment involved the motion of an electron beam in perpendicular electric and magnetic fields to determine the mass-to-charge ratio for the electron. Thomson's experiment demonstrated that electrons are fundamental components of all atoms.

Step-by-step explanation:

The experiment conducted by J.J. Thomson involved the motion of an electron beam in perpendicular electric (E) and magnetic (B) fields to determine the mass-to-charge ratio for the electron. By measuring the extent of deflection of the electron beam in different field strengths, Thomson was able to calculate the mass-to-charge ratio. This experiment demonstrated that cathode rays consisted of charged particles, now known as electrons, which are fundamental components of all atoms.

User Kiduxa
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.