Question

A long straight wire carrying a 3.0A current enters a room through a window 1.5m high and 1.0m wide. The path integral of the magnetic field B around the window frame has a value (in T·m) of:

A) 0.2
B) 2.5ᴇ−7
C) 3.0ᴇ−7
D) 3.8ᴇ−6
E) none of these

Answer 1

To find the path integral of the magnetic field B around the window frame, we can use Ampere's Law. The answer is 9π x 10^-6 T*m, which is not listed among the options given.

Step-by-step explanation:

The question asks for the path integral of the magnetic field B around the window frame. To solve this, we can use Ampere's Law, which states that the integral of B dot dl along a closed loop is equal to the product of the current enclosed by the loop and the permeability of free space (μ0).

In this case, since the wire enters the room through the window, the path integral of B around the window frame is equal to the product of the current in the wire and μ0 multiplied by the area of the window. The area of the window is given by the product of its height and width.

Substituting the given values, we have:

Path Integral of B = (Current in wire) * μ0 * (Window height) * (Window width)

Path Integral of B = (3.0 A) * (4π x 10^-7 T*m/A) * (1.5 m) * (1.0 m)

Simplifying this equation gives us:

Path Integral of B = 9π x 10^-6 T*m

Therefore, the answer is not listed among the options given.