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Find the zero of the function of f(x)=x^3-x^2-10x-8

User Gilzero
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1 Answer

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The zeros of f(x) are: x = -1, x = -2, and x = 4.

Factor the polynomial:

Observe that f(-1) = 0, therefore (x + 1) is a factor.

Use polynomial division to divide f(x) by (x + 1), resulting in the quotient x^2 - 2x - 8.

Further factorize the quotient as (x + 2)(x - 4).

Identify zeros:

Set each factor equal to 0:

x + 1 = 0 --> x = -1

x + 2 = 0 --> x = -2

x - 4 = 0 --> x = 4

Therefore, the zeros of f(x) are: x = -1, x = -2, and x = 4.

User Gyzerok
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