Final answer:
To maximize revenue, the professor should charge $40 per bell.
Step-by-step explanation:
To maximize revenue, we need to find the price at which the demand is highest.
We can find this by taking the derivative of the demand function and setting it equal to zero.
Let's find the derivative first:
q = (80 - 2p)2
Take the derivative of both sides with respect to p:
dq/dp = 2(80 - 2p)(-2) = -4(80 - 2p)
Now set dq/dp equal to zero and solve for p:
-4(80 - 2p) = 0
80 - 2p = 0
-2p = -80
p = 40
So the professor should charge $40 per bell to maximize revenue.