Final answer:
The likely products of the single-replacement reaction between calcium and gold(I) bromide are gold (Au) and calcium bromide (CaBr2), based on the activity series which places calcium as more reactive than gold.
Step-by-step explanation:
The reaction in question appears to be a single-replacement reaction where calcium (Ca) and gold(I) bromide (AuBr, although not a common compound, let's assume it's in line with gold(III) bromide AuBr3) are the reactants. According to the activity series, calcium is more reactive than gold, which means calcium can replace gold in the compound. The chemical equation for the reaction would be:
3 Ca + 2 AuBr3 → 2 Au + 3 CaBr2
Thus, the likely products of this reaction are gold (Au) and calcium bromide (CaBr2).
Note that in actual practice, gold typically forms AuBr3 and not AuBr, but we'll proceed with the given formula for this exercise.