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Develop the line equation having point (4,5 )and (1,2)

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Final answer:

The equation of the line passing through the points (4,5) and (1,2) is found by calculating the slope and then expressing the equation in slope-intercept form, resulting in y = x + 1.

Step-by-step explanation:

To develop the line equation for the points (4,5) and (1,2), we follow these steps:

  1. Calculate the slope (m) using the formula m = (Y2 - Y1) / (X2 - X1), where (X1, Y1) and (X2, Y2) are the given points.
  2. Use one of the points and the slope to write the equation in point-slope form, which is y - y1 = m(x - x1).
  3. Rearrange the equation to slope-intercept form, y = mx + b, where b is the y-intercept.

Now, let's calculate:

  1. Slope calculation: m = (5 - 2) / (4 - 1) = 3 / 3 = 1
  2. Point-slope form: Using point (4,5), the equation is y - 5 = 1(x - 4)
  3. Slope-intercept form: Simplifying the above equation gives us y = x + 1

The equation of the line is y = x + 1.

User Donn Lee
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