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A line passes through the point (6,3) and has a slope of -5/2 Write an equation in slope intercept form for this line.

User Rjbs
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Final answer:

The equation of the line in slope-intercept form, given that it passes through the point (6,3) and has a slope of -5/2, is

y = (-5/2)x + 18.

Step-by-step explanation:

To write the equation of a line in slope-intercept form, which is y = mx + b, we need to know the slope (m) and the y-intercept (b).

Given that the line passes through the point (6,3) and has a slope of -5/2, we can use the point-slope formula to find the equation of the line:

y - y1 = m(x - x1)

Substituting in the point (6,3) and the slope -5/2, we have:

y - 3 = (-5/2)(x - 6)

Distributing the slope on the right side gives us:

y - 3 = (-5/2)x + 15

Adding 3 to both sides to solve for y, we obtain the slope-intercept form of the equation:

y = (-5/2)x + 18