Final answer:
The 0.9% NaCl solution contains 15.4 milliequivalents of Na+ and 15.4 milliequivalents of Cl- in 100 mL of the solution.
Step-by-step explanation:
The concentration of 0.9% NaCl refers to the mass/volume percent, which means that in 100 mL of the solution, there are 0.9 grams of NaCl. To calculate the milliequivalents (mEq) of Na+ and Cl- in the solution, we need to convert the grams of NaCl to moles and then multiply by the molar ratio of the ions.
The molar mass of NaCl is 58.44 g/mol, so 0.9 grams of NaCl is equivalent to 0.0154 moles of NaCl. Since NaCl fully dissociates into Na+ and Cl-, there will be an equal number of moles of Na+ and Cl-. Therefore, the solution contains 0.0154 moles of Na+ and 0.0154 moles of Cl-.
Finally, to calculate the milliequivalents, we need to convert the moles to milliequivalents by multiplying by the valence of the ion. Both Na+ and Cl- have a valence of 1. Therefore, there are 15.4 milliequivalents of Na+ and 15.4 milliequivalents of Cl- in 100 mL of the 0.9% NaCl solution.