∠ABO is 88°. therefore, option 2. 88° is correct.
To find the measure of angle ∠ABO in the quadrilateral ABCD inscribed in a circle with center O, we can use the property that the opposite angles in an inscribed quadrilateral are supplementary.
In this case, ∠BOC is opposite to ∠AOD, and ∠ADC is opposite to ∠ABC. Therefore, we have:
∠AOD + ∠ABC = 180°
Given that ∠BOC = 92° and ∠ADC = 112°, we can substitute these values into the equation:
92° + ∠ABC = 180°
Now, solve for ∠ABC:
∠ABC = 180° - 92°
∠ABC = 88°
Now, ∠ABC is also opposite to ∠ABO. So,
∠ABO = ∠ABC = 88°
Therefore, ∠ABO is 88°. therefore, option 2. 88° is correct.
Question
A quadrilateral ABCD is inscribed in circle with center o. if ∠BOC =92° and ∠ADC =112° then ∠ABO is equal to:
1. 22°
2. 88°
3. 76°
4. 54°