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A 100 kg sled is pulled so it has an acceleration of .5 m/s. The coefficient of kinetic friction between the sled and the snow is .3. What is the applied force on the sled?

User Vinz
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1 Answer

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The applied force on the sled is 494.3 N.

Identify the forces acting on the sled:

Applied force (F): The force pulling the sled forward.

Force of gravity (mg): Pulling the sled downwards.

Normal force (N): The upward force exerted by the snow on the sled (equal to mg).

Friction force (f): Opposing the motion of the sled, acting in the opposite direction of the applied force.

2. Apply Newton's Second Law:

F - f = ma

where:

m is the mass of the sled (100 kg)

a is the acceleration of the sled (0.5 m/s^2)

Calculate the friction force:

f = μkN

where:

μk is the coefficient of kinetic friction (0.3)

N is the normal force (mg)

4. Substitute the values and solve for F:

f = 0.3 * (100 kg * 9.81 m/s^2) = 294.3 N

Substitute the friction force back into the first equation:

F - 294.3 N = 100 kg * 0.5 m/s^2

F = 494.3 N

User Sokmesa Khiev
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