The mass of hydrogen peroxide in a 0.909 M solution, assuming 1 liter of solution, is calculated to be 30.91 grams using the molarity, the volume, and the molar mass of H2O2.
To calculate the mass of hydrogen peroxide (H2O2) in a solution with a molarity of 0.909 M, you would use the formula:
mass (g) = molarity (M) × volume (L) × molar mass (g/mol)
First, identify the volume of the solution. Since molarity is moles of solute per liter of solution, and no volume is provided in the question, let's assume we are dealing with 1 liter (which is a common assumption when the volume is not specified).
Next, we need the molar mass of H2O2. The calculation for the molar mass is:
2×1.008 g/mol (Hydrogen) + 2×15.999 g/mol (Oxygen) = 34.016 g/mol
Now calculate the mass of H2O2:
mass (g) = 0.909 M × 1 L × 34.016 g/mol = 30.90648 g
Therefore, the mass of hydrogen peroxide in a 0.909M solution (assuming 1 liter) is 30.91 grams.