Question

How many joules of heat energy are absorbed when 80.0 g of water are heated from 10.0°C to 50.0°C? *

Answer 1

13440 J

Step-by-step explanation:

c ≈ 4200 J / (kg * °C)

m = 80 g = 0,08 kg

`t_(1)` = 10 °C

`t_(2)` = 50 °C

The formula is: Q = c * m * (
`t_(2) - t_(1)`)

Calculating:

Q = 4200 * 0,08 * (50 - 10) = 13440 (J)