To find the equation in slope-intercept form for a line parallel to y = -3x + 7 that passes through (2, -4), use the fact that parallel lines have the same slope. Substitute the given values into the point-slope form and simplify to get the equation y = -3x + 2.
To find an equation in slope-intercept form for a line parallel to y = -3x + 7 that passes through the point (2, -4), we need to use the fact that parallel lines have the same slope. The given line is in the form y = mx + b, where m represents the slope. So, the slope of the given line is -3. We can use this slope and the given point to find the equation of the parallel line using the point-slope form: y - y1 = m(x - x1).
Substituting the values (2, -4) and m = -3 into the point-slope form, we get: y - (-4) = -3(x - 2). Simplifying this equation gives us the equation in slope-intercept form: y = -3x + 2. Therefore, the equation of the line parallel to y = -3x + 7 that passes through (2, -4) is y = -3x + 2.