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The coordinates of the point JJ are left bracket, 2, comma, minus, 3, right bracket(2,−3) and the coordinates of point KK are left bracket, 2, comma, 9, right bracket, .(2,9). What is the distance, in units, between the point JJ and point K, question markK?

User Negar
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1 Answer

3 votes

Answer:

Therefore, the distance between point J and point K is 12 units.

Explanation:

The distance between two points in a coordinate plane can be calculated using the distance formula:

distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Where:

(x1, y1) are the coordinates of point 1

(x2, y2) are the coordinates of point 2

In this case, point 1 is (2, -3) and point 2 is (2, 9). Plugging these values into the distance formula, we get:

distance = sqrt((2 - 2)^2 + (9 - (-3))^2)

Simplifying the expression, we get:

distance = sqrt(0^2 + 12^2)

distance = sqrt(144)

User Ahvargas
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