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F g(x) = x2 10x with x ≥ −5, find g−1(11).

User Simen S
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Answer:

1. Start with the original function g(x) = x^2 - 10x.

2. Replace g(x) with y to express the function as an equation: y = x^2 - 10x.

3. Swap the x and y variables to switch the roles of the dependent and independent variables: x = y^2 - 10y.

4. Rearrange the equation to isolate y: y^2 - 10y - x = 0.

5. This equation is a quadratic equation in terms of y. To solve it, we can use the quadratic formula: y = (-b ± √(b^2 - 4ac))/(2a), where a = 1, b = -10, and c = -x.

6. Plug in the value of x = 11 into the quadratic formula: y = (-(-10) ± √((-10)^2 - 4(1)(-11)))/(2(1)).

7. Simplify the expression: y = (10 ± √(100 + 44))/2.

8. Further simplify the expression: y = (10 ± √(144))/2.

9. Simplify the square root: y = (10 ± 12)/2.

10. Split the equation into two cases:

a) y = (10 + 12)/2 = 22/2 = 11.

b) y = (10 - 12)/2 = -2/2 = -1.

11. Since we are given x ≥ -5, the only valid solution is y = 11. Therefore, g^(-1)(11) = 11.

In summary, g^(-1)(11) = 11 when considering the given restriction x ≥ -5.

Explanation:

User Nazim Ch
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