Question

baldwin is deep-sea diving with two friends ashley is floating on the surface 7.6 meters above baldwin, and xavier is exploring a coral reef 6 meters in the front of baldwin how far apart are ashley and xavier ?

Answer 1

To find the distance between Ashley and Xavier, we form a right-angled triangle using their relative positions and apply the Pythagorean theorem, yielding a result of approximately 9.68 meters.

Step-by-step explanation:

The question involves calculating the distance between two points in a three-dimensional space, where Ashley is floating on the surface above Baldwin and Xavier is in front of Baldwin. This is a Pythagorean theorem problem in three dimensions. We can form a right-angled triangle with the distances given.

To find the distance between Ashley and Xavier, we use the Pythagorean theorem in the form of d = √(x^2 + y^2 + z^2), where d is the distance between Ashley and Xavier, x is the horizontal distance between Baldwin and Xavier, y is zero since they are level with each other on a vertical plane, and z is the vertical distance between Ashley and Baldwin.

Since Xavier is 6 meters in front of Baldwin and Ashley is 7.6 meters above Baldwin, we have:

d = √(6^2 + 0^2 + 7.6^2)

d = √(36 + 0 + 57.76)

d = √93.76

d ≈ 9.68 meters

Thus, Ashley and Xavier are approximately 9.68 meters apart.