Final answer:
To find the distance between Ashley and Xavier, we form a right-angled triangle using their relative positions and apply the Pythagorean theorem, yielding a result of approximately 9.68 meters.
Step-by-step explanation:
The question involves calculating the distance between two points in a three-dimensional space, where Ashley is floating on the surface above Baldwin and Xavier is in front of Baldwin. This is a Pythagorean theorem problem in three dimensions. We can form a right-angled triangle with the distances given.
To find the distance between Ashley and Xavier, we use the Pythagorean theorem in the form of d = √(x^2 + y^2 + z^2), where d is the distance between Ashley and Xavier, x is the horizontal distance between Baldwin and Xavier, y is zero since they are level with each other on a vertical plane, and z is the vertical distance between Ashley and Baldwin.
Since Xavier is 6 meters in front of Baldwin and Ashley is 7.6 meters above Baldwin, we have:
d = √(6^2 + 0^2 + 7.6^2)
d = √(36 + 0 + 57.76)
d = √93.76
d ≈ 9.68 meters
Thus, Ashley and Xavier are approximately 9.68 meters apart.