Final answer:
The displacement vector from AB to A'B' is (5, 6).
Step-by-step explanation:
The given points are (-6, -3) and (-3, -9) for AB and (-2, -1) and (-1, -3) for A'B'.
To find the displacement vector from AB to A'B', we subtract the coordinates of AB from the coordinates of A'B'.
The displacement vector from AB to A'B' is obtained by subtracting the x-coordinates and the y-coordinates separately: (-1 - (-6), -3 - (-9)) = (5, 6).