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Exponential equations not requiring logarithms
4^2x+3 = 1​

User Kroid
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1 Answer

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Final answer:

The exponential equation 4^(2x + 3) = 1 can be solved by equating 2x + 3 to 0 since any base raised to the power of 0 equals 1. Subtracting 3 from both sides and then dividing by 2 yields the solution x = -3/2.

Step-by-step explanation:

The question asks us to solve an exponential equation that does not require the use of logarithms: 4^(2x + 3) = 1. To solve this, we can make use of the property that any non-zero number raised to the power of 0 is equal to 1, i.e., b^0 = 1. Since 1 can be written as 4^0, we can deduce that 2x + 3 must be equal to 0 for the equation to hold true.

Thus, we have 2x + 3 = 0. To find x, we subtract 3 from both sides and then divide by 2. This gives us:

  • 2x + 3 - 3 = 0 - 3
  • 2x = -3
  • x = -3 / 2

So, the solution to the equation 4^(2x + 3) = 1 is x = -3/2.

User Shun Yamada
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