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What is the standard equation of this hyperbola 9²−36²=36?

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The standard equation of a hyperbola is usually written in the form:

\(\frac{(x - h)^2}{a^2} - \frac{(y - k)^2}{b^2} = 1\) for a horizontal transverse axis or
\(\frac{(y - k)^2}{a^2} - \frac{(x - h)^2}{b^2} = 1\) for a vertical transverse axis.

However, the equation you've provided, \(9^2 - 36^2 = 36\), doesn't resemble the standard form of a hyperbola.

If you meant to write the equation in a standard form related to a hyperbola, it might be \(9x^2 - 36y^2 = 36\) or something similar. In this case, the equation could be rearranged into the standard form of a hyperbola by dividing each term by 36:

\(\frac{x^2}{4} - \frac{y^2}{1} = 1\)

This would represent a hyperbola with a horizontal transverse axis, centered at the origin, with vertices at (-2, 0) and (2, 0), and asymptotes passing through those points.
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