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A box contains 3 blue and 8 white balls.A ball is drawn at random from the box without replacement.What is the probability of drawing one blue and one white ball? Explain the answer

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Final answer:

The probability of drawing one blue and one white ball from a box containing 3 blue balls and 8 white balls without replacement is 24/55.

Step-by-step explanation:

To find the probability of drawing one blue and one white ball from the box, we can use the concept of combinations and the principles of probability. There are a total of 11 balls in the box, and we need to draw two balls without replacement. The number of ways to select one blue ball and one white ball can be found by multiplying the number of ways to select 1 blue ball from 3 and 1 white ball from 8. This can be calculated as:

P(1 blue and 1 white) = (C(3, 1) * C(8, 1)) / C(11, 2) = (3 * 8) / 55 = 24/55.

Therefore, the probability of drawing one blue and one white ball is 24/55.

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