Question

Let p=x²-7.

Which equation is equivalent to (x²-7)²-4x²+28=5 in terms of p?
a. p²+4p-5=0
b. p²-4p+23=0
c. p²4p-5=0
d. p²+4p+23=0

Answer 1

The equation equivalent to (x²-7)²-4x²+28=5 in terms of p is p²-4p+23=0.

Step-by-step explanation:

To find which equation is equivalent to (x²-7)²-4x²+28=5 in terms of p, we substitute the expression p for x²-7. So the equation becomes:

(p)²-4(p)+28=5

Simplifying:

p²-4p+28=5

Therefore, the equation equivalent to (x²-7)²-4x²+28=5 in terms of p is p²-4p+23=0.