Question

When lead(II) sulfide is heated to high temperatures in a stream of pure oxygen gas, solid lead(II) oxide forms with the release of gaseous sulfur dioxide. Write the unbalanced chemical equation for this reaction. (Omit states-of-matter in your answer.)

Answer 1

Lead(II) sulfide reacts with oxygen gas to form lead(II) oxide and sulfur dioxide gas, represented by the unbalanced equation PbS + O2 → PbO + SO2.

Step-by-step explanation:

When lead(II) sulfide is heated to high temperatures in a stream of pure oxygen gas, the reaction that takes place is the oxidation of lead(II) sulfide to lead(II) oxide with the release of sulfur dioxide gas. The unbalanced chemical equation for this reaction is:

PbS + O2 → PbO + SO2

This reaction involves a combination of elements and compounds where lead(II) sulfide is combined with oxygen leading to the formation of lead(II) oxide and the evolution of sulfur dioxide gas.