Final answer:
The quantity of moles of glucose in 0.500 L of a 0.400 M solution is calculated by multiplying the volume of the solution by its molarity, which gives 0.200 moles of glucose.
Step-by-step explanation:
To calculate the quantity of moles of glucose (C6H12O6) in a solution, we multiply the volume of the solution by its molarity. Given the question 'What quantity of moles of glucose is in 0.500 L of a 0.400 M solution?', we proceed with the following calculation:
VLMmol/L = moles
Therefore:
- Volume (V) = 0.500 L
- Molarity (M) = 0.400 mol/L
By multiplying the volume by the molarity, we get:
0.500 L × 0.400 mol/L = 0.200 moles of glucose
This is the quantity of moles of glucose present in the given volume of the solution. It is important to ensure that the units of volume are in liters (L) and that the molarity is in moles per liter (mol/L) before performing the multiplication to obtain the correct number of moles.