Question

What mass of fe can be produced by the reaction of 75.0 g co with excess fe2o3 according to the equation: fe2o3(s) 3co(g) → 2fe(s) 3co2(g)? 49.8 g fe

Answer 1

To find the mass of iron (Fe) produced when 75.0 g of carbon monoxide (CO) reacts with excess iron(III) oxide (Fe2O3), we’ll use stoichiometry and the given balanced chemical equation:

Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)

First, we need to determine the number of moles of CO (carbon monoxide) in 75.0 g:

Molar mass of CO (carbon monoxide):
C: 12.01 g/mol
O: 16.00 g/mol
Total: 12.01 g/mol + 16.00 g/mol = 28.01 g/mol

Number of moles = Mass / Molar mass
Number of moles of CO = 75.0 g / 28.01 g/mol ≈ 2.68 mol

Now, we use the mole ratio between CO and Fe from the balanced chemical equation:

From the balanced equation, 3 moles of CO react to produce 2 moles of Fe.

3 moles of CO → 2 moles of Fe
2.68 moles of CO → (2/3) * 2.68 moles of Fe ≈ 1.79 moles of Fe

Now, calculate the mass of Fe produced using the molar mass of Fe:

Molar mass of Fe (iron) = 55.85 g/mol

Mass of Fe produced = Number of moles × Molar mass
Mass of Fe produced = 1.79 moles × 55.85 g/mol ≈ 99.87 g

Therefore, according to the stoichiometry of the reaction, the expected mass of Fe produced from the reaction of 75.0 g of CO with excess Fe2O3 is approximately 99.87 grams, which is different from the value provided (49.8 g Fe). This discrepancy might be due to calculation errors or incorrect assumptions in the problem description or provided answer.

Answer 2

To find the mass of CO required to react with Fe₂O3, use stoichiometry and the balanced chemical equation. Convert the given mass of Fe₂O3 to moles, then use the mole ratio to convert moles of Fe₂O3 to moles of CO. Finally, convert the moles of CO to grams using its molar mass.

Step-by-step explanation:

To determine the mass of CO required to react with 25.13 g of Fe₂O3, we can use stoichiometry and the balanced chemical equation. The balanced equation Fe2O3 + 3CO → 2Fe + 3CO₂ shows that for every 1 mole of Fe₂O3, we need 3 moles of CO. First, we calculate the number of moles of Fe₂O3 using its molar mass (159.70 g/mol).

Next, we use the mole ratio from the balanced equation to convert moles of Fe₂O3 to moles of CO. Since the ratio is 3 moles of CO to 1 mole of Fe₂O3, we multiply the moles of Fe₂O3 by 3.

Finally, we convert the moles of CO to grams using its molar mass (28.01 g/mol). The mass of CO required is therefore found by multiplying the moles of CO by its molar mass.