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What is the molarity of chloride solutions in a 1.0 l solution containing 50.0 g of magnesium chloride? (

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Final answer:

The molarity of a 1.0 L solution containing 50.0 g of magnesium chloride is calculated by dividing the number of moles of magnesium chloride by the volume of the solution, resulting in a molarity of 0.525 M.

Step-by-step explanation:

Calculating the Molarity of Magnesium Chloride Solution

To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters. Molarity (M) is defined as the number of moles of solute divided by the volume of the solution in liters. For magnesium chloride (MgCl2), the molar mass is approximately 95.21 g/mol. Using the given data:



The number of moles of MgCl2 can be calculated by dividing the mass by the molar mass:

Number of moles = Mass / Molar mass = 50.0 g / 95.21 g/mol = 0.525 moles (approximately)

Now, we can calculate the molarity:

Molarity (M) = Number of moles / Volume (L) = 0.525 moles / 1.0 L = 0.525 M

Therefore, the molarity of the magnesium chloride solution is 0.525 M.

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