Final answer:
To determine the energy level of Li²⁺ when it is excited to n=4, the Bohr model formula is used with the principal quantum number n=4, the atomic number Z=3 for Lithium, and the constant k=2.18 × 10⁻¹⁸ J.
Step-by-step explanation:
When discussing the energy level of Li2+ when it is excited to an energy level of n=4, we're looking at a problem that applies the Bohr model of the hydrogen-like ion, Li2+. Specifically, we use the Bohr formula to calculate the energy levels of the electron:
En = - (k * Z2) / n2
Where k is a constant equal to 2.18 × 10⁻¹⁸ J, Z is the atomic number for Lithium (which is 3), and n is the principal quantum number corresponding to the energy level. The question provided by the student seems to have mixed some variables and possibly a different context, as there is a mention of different transitions which do not relate directly to the original question.
The energy of an electron in the fourth energy level (n=4) is calculated as follows:
E4 = - (2.18 × 10⁻¹⁸ J * 32) / 42
By simplifying this formula, we can get the energy for Li2+ at n=4.